What is the answer to (1+i)x+(-2+i)y=-3+16i ?

The answer to (1+i)x+(-2+i)y=-3+16i is x= 29/3 ,y= 19/3

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(1+i)x+(-2+i)y=-3+16i

(1 + i) x + (- 2 + i) y = - 3 + 16 i

x = \frac{29}{3}, y = \frac{19}{3}

Solution steps

(1 + i) x + (- 2 + i) y = - 3 + 16 i

Rewrite

(1 + i) x + (- 2 + i) y

in standard complex form:

(x - 2 y) + (x + y) i

(x - 2 y) + (x + y) i = - 3 + 16 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - 2 y = - 3 x + y = 16]

[x - 2 y = - 3 x + y = 16] : x = \frac{29}{3}, y = \frac{19}{3}

x = \frac{29}{3}, y = \frac{19}{3}

24 + 42 y i = - 0.5 x + 0.5 i

6 (4 + 7 i)^{2} + A (4 + 7 i) + B = 0

x + i y = 1, 1 x + y = 1 + i

3 x^{2} - 125 i x - 3500 = 121 i x + 1543

a - bi = - b + ia

What is the answer to (1+i)x+(-2+i)y=-3+16i ?
The answer to (1+i)x+(-2+i)y=-3+16i is x= 29/3 ,y= 19/3