What is the answer to m=p[(1+i)t-1]i ?

The answer to m=p[(1+i)t-1]i is p=-m,t=1,\quad m\ne 0

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m=p[(1+i)t-1]i

m = p [(1 + i) t - 1] i

p = - m, t = 1, m \neq = 0

Solution steps

m = p [(1 + i) t - 1] i

Simplify

p ((1 + i) t - 1) i : - pt + i p (t - 1)

m = - pt + i p (t - 1)

Rewrite

m

in standard complex form:

m + 0 i

m + 0 i = - pt + i p (t - 1)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[m = - pt 0 = pt - p]

[m = - pt 0 = pt - p] : p = - m, t = 1, m \neq = 0

p = - m, t = 1, m \neq = 0

a - bi = - b + ai

(3 - 4 i) (a + bi) = 25

(z^{1})^{2} = (2 - 5 i)^{2}

a + bi = - 9 + 4 i

a + ib = 1 - (a - ib) + 3 i

What is the answer to m=p[(1+i)t-1]i ?
The answer to m=p[(1+i)t-1]i is p=-m,t=1,\quad m\ne 0