What is the answer to (x+y)+(x-y)i=3+2i ?

The answer to (x+y)+(x-y)i=3+2i is x= 5/2 ,y= 1/2

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(x+y)+(x-y)i=3+2i

(x + y) + (x - y) i = 3 + 2 i

x = \frac{5}{2}, y = \frac{1}{2}

Solution steps

(x + y) + (x - y) i = 3 + 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + y = 3 x - y = 2]

[x + y = 3 x - y = 2] : x = \frac{5}{2}, y = \frac{1}{2}

x = \frac{5}{2}, y = \frac{1}{2}

x^{2} = 16 i

x^{2} - x - i = 0

∣ z ∣ = 2 - 3 i + z

z^{2} + 1 = (z + i) (z - i)

(2 + i) x = y

What is the answer to (x+y)+(x-y)i=3+2i ?
The answer to (x+y)+(x-y)i=3+2i is x= 5/2 ,y= 1/2