What is the answer to 3x-4y+(6x+2y)i=5i ?

The answer to 3x-4y+(6x+2y)i=5i is x= 2/3 ,y= 1/2

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3x-4y+(6x+2y)i=5i

3 x - 4 y + (6 x + 2 y) i = 5 i

x = \frac{2}{3}, y = \frac{1}{2}

Solution steps

3 x - 4 y + (6 x + 2 y) i = 5 i

Rewrite

5 i

in standard complex form:

0 + 5 i

3 x - 4 y + (6 x + 2 y) i = 0 + 5 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 x - 4 y = 0 6 x + 2 y = 5]

[3 x - 4 y = 0 6 x + 2 y = 5] : x = \frac{2}{3}, y = \frac{1}{2}

x = \frac{2}{3}, y = \frac{1}{2}

s i \frac{x}{3} + 2 x = 7, x

z = (- 3 - 2 i) (3 + x i)

\frac{z - 1}{z} = 3 + 4 i

25 - m^{2} = (- 1)^{2} + (mi + 2 i)^{2}

\frac{z - 5 i}{z + 2} = 4 i

What is the answer to 3x-4y+(6x+2y)i=5i ?
The answer to 3x-4y+(6x+2y)i=5i is x= 2/3 ,y= 1/2