What is the answer to (x-2yi)-(y-xi)=2+i ?

The answer to (x-2yi)-(y-xi)=2+i is x=3,y=1

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(x-2yi)-(y-xi)=2+i

(x - 2 y i) - (y - x i) = 2 + i

x = 3, y = 1

Solution steps

(x - 2 y i) - (y - x i) = 2 + i

Rewrite

(x - 2 y i) - (y - x i)

in standard complex form:

(x - y) + (- 2 y + x) i

(x - y) + (- 2 y + x) i = 2 + i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - y = 2 - 2 y + x = 1]

[x - y = 2 - 2 y + x = 1] : x = 3, y = 1

x = 3, y = 1

z - (\frac{1}{z}) = 1 + 5 i

z^{2} = - (\frac{4 i}{3})

\frac{1 + i}{z} - (4 + 3 i) = i

z^{2} - (5 + 2 i) z + 1 = 0

+ 6 i z^{2} = 3 + 5 i, z^{1} = 2

What is the answer to (x-2yi)-(y-xi)=2+i ?
The answer to (x-2yi)-(y-xi)=2+i is x=3,y=1