What is the answer to 22(x+yi)+(28+4i)=72-62i ?

The answer to 22(x+yi)+(28+4i)=72-62i is x=2,y=-3

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22(x+yi)+(28+4i)=72-62i

22 (x + y i) + (28 + 4 i) = 72 - 62 i

x = 2, y = - 3

Solution steps

22 (x + y i) + (28 + 4 i) = 72 - 62 i

Rewrite

22 (x + y i) + (28 + 4 i)

in standard complex form:

(22 x + 28) + (22 y + 4) i

(22 x + 28) + (22 y + 4) i = 72 - 62 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[22 x + 28 = 72 22 y + 4 = - 62]

[22 x + 28 = 72 22 y + 4 = - 62] : x = 2, y = - 3

x = 2, y = - 3

a x^{2} - b x + 9 + 3 i = 0

2 i (a + bi) + 6 = 9 i + (a + bi)

(x + i y)^{2} = 3 + 2 i

(9 - 7 i) - 7 = x - (7 + y i)

(x + i y) + 2 (x - i y) = \frac{2 i}{1 + 2 i}

What is the answer to 22(x+yi)+(28+4i)=72-62i ?
The answer to 22(x+yi)+(28+4i)=72-62i is x=2,y=-3