What is the answer to i(x-iy)=-i(x-iy) ?

The answer to i(x-iy)=-i(x-iy) is x=0,y=0

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i(x-iy)=-i(x-iy)

i (x - i y) = - i (x - i y)

x = 0, y = 0

Solution steps

i (x - i y) = - i (x - i y)

Simplify

y + i x = - y - i x

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[y = - y x = - x]

[y = - y x = - x] : x = 0, y = 0

x = 0, y = 0

(1 + i) z^{2} + (2 - i) z + (1 + 3 i) = 0

z^{2} = 49 + i

z^{2} + (2 i - 3) z + 5 - 1 = 0

s i f (x) = \frac{5 x ^{2}}{x}, f (0)

z^{2} + 4 z i - 4 = 0

What is the answer to i(x-iy)=-i(x-iy) ?
The answer to i(x-iy)=-i(x-iy) is x=0,y=0