What is the answer to z-5=i(10+4^-z) ?

The answer to z-5=i(10+4^-z) is No Solution

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z-5=i(10+4^-z)

z - 5 = i (10 + 4^{-} z)

No Solution

Solution steps

z - 5 = i (10 + 4^{-} z)

Substitute

z = x + y i

x + y i - 5 = i (10 + 4^{-} (x + y i))

Simplify

(x - 5) + i y = - 4^{-} y + i (10 + 4^{-} x)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x - 5 = - 4^{-} y y = 10 + 4^{-} x]

[x - 5 = - 4^{-} y y = 10 + 4^{-} x] : No Solution

Substitute back

z = x + y i

No Solution

r - 8 = r - i

3 x - 4 = y i + i

\frac{z - 1}{z} = 3 + 2 i

Z^{2} = 7 + 3 i

x y - x i + 2 i y - 2 i^{2} = - 4 - 7 i

What is the answer to z-5=i(10+4^-z) ?
The answer to z-5=i(10+4^-z) is No Solution