What is the answer to x^2-7x+9yi=y^2i+20yi-12 ?

The answer to x^2-7x+9yi=y^2i+20yi-12 is

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x^2-7x+9yi=y^2i+20yi-12

x^{2} - 7 x + 9 y i = y^{2} i + 20 y i - 12

x = 3, x = 3, x = 4, x = 4, y = 0 y = - 11 y = 0 y = - 11

Solution steps

x^{2} - 7 x + 9 y i = y^{2} i + 20 y i - 12

Rewrite

y^{2} i + 20 y i - 12

in standard complex form:

- 12 + (y^{2} + 20 y) i

x^{2} - 7 x + 9 y i = - 12 + (y^{2} + 20 y) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x^{2} - 7 x = - 12 9 y = y^{2} + 20 y]

[x^{2} - 7 x = - 12 9 y = y^{2} + 20 y] : x = 3, x = 3, x = 4, x = 4, y = 0 y = - 11 y = 0 y = - 11

x = 3, x = 3, x = 4, x = 4, y = 0 y = - 11 y = 0 y = - 11

a + bi - 5 = i (10 + 4 (a + bi))

z^{2} + 2 i z + 3 = 0

(1 + q) (2 + i) + p = ((p + q - 1) (3 + i) + 2)

a^{2} - 4 ia - 4 = 0

\frac{i \cdot z - 3}{z ^{2} - 1} = - 1

What is the answer to x^2-7x+9yi=y^2i+20yi-12 ?
The answer to x^2-7x+9yi=y^2i+20yi-12 is