What is the answer to (3b-2ai)/(4-3i)=0 ?

The answer to (3b-2ai)/(4-3i)=0 is a=0,b=0

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(3b-2ai)/(4-3i)=0

\frac{3 b - 2 ai}{4 - 3 i} = 0

a = 0, b = 0

Solution steps

\frac{3 b - 2 ai}{4 - 3 i} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 b - 2 ai = 0

Rewrite

0

in standard complex form:

0 + 0 i

3 b - 2 ai = 0 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 b = 0 - 2 a = 0]

[3 b = 0 - 2 a = 0] : a = 0, b = 0

a = 0, b = 0

5 + (5 x + y) i = 5 x - 2 i

∣ z ∣ + z = 2 + i

z^{2} = \frac{1 + i 3}{2}

x^{2} = 4 + 415 i

((a + bi) + 2)^{2} = - 2 i

What is the answer to (3b-2ai)/(4-3i)=0 ?
The answer to (3b-2ai)/(4-3i)=0 is a=0,b=0