What is the answer to (a-bi)=i(a+bi) ?

The answer to (a-bi)=i(a+bi) is No Solution

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(a-bi)=i(a+bi)

(a - bi) = i (a + bi)

No Solution

Solution steps

(a - bi) = i (a + bi)

Simplify

a - ib = - b + ia

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a = - b - b = a]

[a = - b - b = a] : No Solution

No Solution

b^{2} = 3^{2} + (3 i)^{2}

- \frac{1}{z - i} + 1 - z = 0

+ 5 i z^{2} = - 2 + 3 i, z^{1} = 4

z^{1} + z^{2} = (4 + 3) + (2 + 5) i

z^{2} - (1 + 4 i) z - (6 - 12 i) = 0

What is the answer to (a-bi)=i(a+bi) ?
The answer to (a-bi)=i(a+bi) is No Solution