What is the answer to (2x-i)+(x-2yi)=-2i ?

The answer to (2x-i)+(x-2yi)=-2i is x=0,y= 1/2

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(2x-i)+(x-2yi)=-2i

(2 x - i) + (x - 2 y i) = - 2 i

x = 0, y = \frac{1}{2}

Solution steps

(2 x - i) + (x - 2 y i) = - 2 i

Rewrite

(2 x - i) + (x - 2 y i)

in standard complex form:

3 x + (- 1 - 2 y) i

3 x + (- 1 - 2 y) i = - 2 i

Rewrite

- 2 i

in standard complex form:

0 - 2 i

3 x + (- 1 - 2 y) i = 0 - 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 x = 0 - 1 - 2 y = - 2]

[3 x = 0 - 1 - 2 y = - 2] : x = 0, y = \frac{1}{2}

x = 0, y = \frac{1}{2}

\frac{( 1 - z )}{( 1 + z )} = 2 i

(x + i y)^{2} + i x + y - 4 = 0

∣ z ∣ + z = 3 + i

(z^{2} - 4 i z - 1) = 0

∣ 3 z + 2 i ∣ = 6

What is the answer to (2x-i)+(x-2yi)=-2i ?
The answer to (2x-i)+(x-2yi)=-2i is x=0,y= 1/2