What is the answer to (a-bi)+(b+ai)=5+i ?

The answer to (a-bi)+(b+ai)=5+i is a=3,b=2

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(a-bi)+(b+ai)=5+i

(a - bi) + (b + ai) = 5 + i

a = 3, b = 2

Solution steps

(a - bi) + (b + ai) = 5 + i

Rewrite

(a - bi) + (b + ai)

in standard complex form:

(a + b) + (- b + a) i

(a + b) + (- b + a) i = 5 + i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a + b = 5 - b + a = 1]

[a + b = 5 - b + a = 1] : a = 3, b = 2

a = 3, b = 2

z^{2} - 2 z = 3 i

i = 2 x^{2} + x - 2

(a - bi) (a + bi) + (a - bi) = 3 - i

(x - y) + 8 i = 6 + y i

2 p - q + i (7 i + 3) = 2 (2 i - q) - i (p + 3 q)

What is the answer to (a-bi)+(b+ai)=5+i ?
The answer to (a-bi)+(b+ai)=5+i is a=3,b=2