What is the answer to (3k+2)+(4m)i=-4+20i ?

The answer to (3k+2)+(4m)i=-4+20i is k=-2,m=5

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(3k+2)+(4m)i=-4+20i

(3 k + 2) + (4 m) i = - 4 + 20 i

k = - 2, m = 5

Solution steps

(3 k + 2) + (4 m) i = - 4 + 20 i

Rewrite

(3 k + 2) + (4 m) i

in standard complex form:

(3 k + 2) + 4 mi

(3 k + 2) + 4 mi = - 4 + 20 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 k + 2 = - 4 4 m = 20]

[3 k + 2 = - 4 4 m = 20] : k = - 2, m = 5

k = - 2, m = 5

x (3 - i) + (y - x i) = - 3 + 4 i

2 (y + i) = y^{2}

i (x) = - \frac{x ^{2}}{4} + 3450 x

(x - i) (x + i) = 0

x + y \cdot i = i

What is the answer to (3k+2)+(4m)i=-4+20i ?
The answer to (3k+2)+(4m)i=-4+20i is k=-2,m=5