What is the answer to 2x+y+(x-y)i=7+8i ?

The answer to 2x+y+(x-y)i=7+8i is x=5,y=-3

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2x+y+(x-y)i=7+8i

2 x + y + (x - y) i = 7 + 8 i

x = 5, y = - 3

Solution steps

2 x + y + (x - y) i = 7 + 8 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 x + y = 7 x - y = 8]

[2 x + y = 7 x - y = 8] : x = 5, y = - 3

x = 5, y = - 3

x^{2} - 5 i x + 6 = 0

t, \frac{q}{t} = 2 i

a - bi = ai - b i^{2}

s i f (x) = \frac{( 2 x - 1 )}{2 x + 1}

i (x) = e (2 x^{2} - 1)

What is the answer to 2x+y+(x-y)i=7+8i ?
The answer to 2x+y+(x-y)i=7+8i is x=5,y=-3