What are the solutions to the equation (7x+22)^2=80 ?

The solutions to the equation (7x+22)^2=80 are x=(4sqrt(5)-22)/7 ,x=(-4sqrt(5)-22)/7

Find the zeros of (7x+22)^2=80

The zeros of (7x+22)^2=80 are x=(4sqrt(5)-22)/7 ,x=(-4sqrt(5)-22)/7

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(7 x + 22)^{2} = 80

x = \frac{4 5 - 22}{7}, x = \frac{- 4 5 - 22}{7}

Decimal Notation

x = - 1.86510 \dots, x = - 4.42061 \dots

Solution steps

(7 x + 22)^{2} = 80

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 22 = 80 : x = \frac{4 5 - 22}{7}

Solve

7 x + 22 = - 80 : x = \frac{- 4 5 - 22}{7}

The solutions to the quadratic equation are:

x = \frac{4 5 - 22}{7}, x = \frac{- 4 5 - 22}{7}

\frac{6}{8}

(125 x^{- 3} y^{- 15})^{\frac{5}{3}}

\frac{1}{4} (- 4)

9 y^{2} x^{2} + 24 y x^{2} + 16 x^{2}

∣ x ∣ < - 12

What are the solutions to the equation (7x+22)^2=80 ?
The solutions to the equation (7x+22)^2=80 are x=(4sqrt(5)-22)/7 ,x=(-4sqrt(5)-22)/7
Find the zeros of (7x+22)^2=80
The zeros of (7x+22)^2=80 are x=(4sqrt(5)-22)/7 ,x=(-4sqrt(5)-22)/7