What is the answer to (5-3i)y-(6+2i)x=3-41i ?

The answer to (5-3i)y-(6+2i)x=3-41i is x=7,y=9

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(5-3i)y-(6+2i)x=3-41i

(5 - 3 i) y - (6 + 2 i) x = 3 - 41 i

x = 7, y = 9

Solution steps

(5 - 3 i) y - (6 + 2 i) x = 3 - 41 i

Rewrite

(5 - 3 i) y - (6 + 2 i) x

in standard complex form:

(5 y - 6 x) + (- 3 y - 2 x) i

(5 y - 6 x) + (- 3 y - 2 x) i = 3 - 41 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[5 y - 6 x = 3 - 3 y - 2 x = - 41]

[5 y - 6 x = 3 - 3 y - 2 x = - 41] : x = 7, y = 9

x = 7, y = 9

x^{2} + y^{2} - (x + i y) = 1 + 0 i

a = [aij]

∣ z + 1 - i ∣ = 1

\frac{2 - 2 i}{4} = \frac{1 - 2 i}{z}

i z + (1 + 2 i) w = 25

What is the answer to (5-3i)y-(6+2i)x=3-41i ?
The answer to (5-3i)y-(6+2i)x=3-41i is x=7,y=9