What is the answer to i=(70*10e^{-9})/(5s) ?

The answer to i=(70*10e^{-9})/(5s) is s=-(140)/(e^9)i

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i=(70*10e^{-9})/(5s)

i = \frac{70 \cdot 10 e ^{- 9}}{5 s}

s = - \frac{140}{e ^{9}} i

Solution steps

i = \frac{70 \cdot 10 e ^{- 9}}{5 s}

Substitute

s = x + y i

i = \frac{70 \cdot 10 e ^{- 9}}{5 ( x + y i )}

Multiply both sides by

5 x + 5 i y

i (5 x + 5 i y) = \frac{70 \cdot 10 e ^{- 9}}{5 ( x + y i )} (5 x + 5 i y)

Simplify

- 5 y + 5 i x = \frac{700}{e ^{9}}

Rewrite

\frac{700}{e ^{9}}

in standard complex form:

\frac{700}{e ^{9}} + 0 i

- 5 y + 5 i x = \frac{700}{e ^{9}} + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 5 y = \frac{700}{e ^{9}} 5 x = 0]

[- 5 y = \frac{700}{e ^{9}} 5 x = 0] : x = 0, y = - \frac{140}{e ^{9}}

Substitute back

s = x + y i

s = - \frac{140}{e ^{9}} i

e = \frac{( i \cdot n ^{2} )}{( 179 )}

(x + y i)^{2} = 4 i

x + - 64 = 3 + y i

(1 + i) z^{2} + z - 5 = 0

z^{2} + (3 - 2 i) z + 5 - i = 0

What is the answer to i=(70*10e^{-9})/(5s) ?
The answer to i=(70*10e^{-9})/(5s) is s=-(140)/(e^9)i