What is the answer to a^2+b^2+a-bi=11+3i ?

The answer to a^2+b^2+a-bi=11+3i is

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a^2+b^2+a-bi=11+3i

a^{2} + b^{2} + a - bi = 11 + 3 i

(a = 1, a = - 2, b = - 3 b = - 3)

Solution steps

a^{2} + b^{2} + a - bi = 11 + 3 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[a^{2} + b^{2} + a = 11 - b = 3]

[a^{2} + b^{2} + a = 11 - b = 3] : (a = 1, a = - 2, b = - 3 b = - 3)

(a = 1, a = - 2, b = - 3 b = - 3)

t, a = \frac{V f - Vi}{t}

\frac{1}{z} = 1 - i

(x + y) + i (2 x - 3 y) = 2 + i

(x i)^{2} + 125.6637 x i + 1184 = 0

x + i y + 2 x - 2 i = \frac{2 - i}{1 + 3 i}