What is the answer to a(2-i)+b(3+i)=10 ?

The answer to a(2-i)+b(3+i)=10 is a=2,b=2

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a(2-i)+b(3+i)=10

a (2 - i) + b (3 + i) = 10

a = 2, b = 2

Solution steps

a (2 - i) + b (3 + i) = 10

Rewrite

a (2 - i) + b (3 + i)

in standard complex form:

(2 a + 3 b) + (- a + b) i

(2 a + 3 b) + (- a + b) i = 10

Rewrite

10

in standard complex form:

10 + 0 i

(2 a + 3 b) + (- a + b) i = 10 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 a + 3 b = 10 - a + b = 0]

[2 a + 3 b = 10 - a + b = 0] : a = 2, b = 2

a = 2, b = 2

i z^{2} - 2 z + 3 i = 0

- 1 - i = x i + y

\frac{a + bi - 2}{a + bi + 1} = 3 i

a + bi = 8 i

(x + y i)^{2} = 3 - 4

What is the answer to a(2-i)+b(3+i)=10 ?
The answer to a(2-i)+b(3+i)=10 is a=2,b=2