What is the answer to (9-8i)-6=x-(2+yi) ?

The answer to (9-8i)-6=x-(2+yi) is x=5,y=8

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(9-8i)-6=x-(2+yi)

(9 - 8 i) - 6 = x - (2 + y i)

x = 5, y = 8

Solution steps

(9 - 8 i) - 6 = x - (2 + y i)

Rewrite

(9 - 8 i) - 6

in standard complex form:

3 - 8 i

3 - 8 i = x - (2 + y i)

Rewrite

x - (2 + y i)

in standard complex form:

(x - 2) - y i

3 - 8 i = (x - 2) - y i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 = x - 2 - 8 = - y]

[3 = x - 2 - 8 = - y] : x = 5, y = 8

x = 5, y = 8

(x + i y) (4 i) = 8

\frac{1285}{8} - 60 i = 1 0^{6} M^{2}

x + y i = (1 - i)^{2}

\frac{1 + z}{1 - z} = 8 i - 5

\frac{1 + 2 z}{3 + 2 z} = i

What is the answer to (9-8i)-6=x-(2+yi) ?
The answer to (9-8i)-6=x-(2+yi) is x=5,y=8