What is the answer to 4a-3i=6+bi ?

The answer to 4a-3i=6+bi is a= 3/2 ,b=-3

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4a-3i=6+bi

4 a - 3 i = 6 + bi

a = \frac{3}{2}, b = - 3

Solution steps

4 a - 3 i = 6 + bi

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[4 a = 6 - 3 = b]

[4 a = 6 - 3 = b] : a = \frac{3}{2}, b = - 3

a = \frac{3}{2}, b = - 3

∣ a - i ∣ = 37

x^{2} - 2 i x - 2 = 0

(x + y i) + 4 (1 - i) = 5 - 7 i

z^{2} - (5 + 4 i) z + (3 - 5 i) = 0

x^{2} + 3 x + 2 - i = 0