What is factor x^2+4x+3x+12 ?

The solution to factor x^2+4x+3x+12 is (x+3)(x+4)

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factor x^2+4x+3x+12

factor

x^{2} + 4 x + 3 x + 12

(x + 3) (x + 4)

Solution steps

x^{2} + 4 x + 3 x + 12

Add similar elements:

4 x + 3 x = 7 x

= x^{2} + 7 x + 12

Break the expression into groups

= (x^{2} + 3 x) + (4 x + 12)

Factor out

x

from

x^{2} + 3 x : x (x + 3)

Factor out

4

from

4 x + 12 : 4 (x + 3)

= x (x + 3) + 4 (x + 3)

Factor out common term

x + 3

= (x + 3) (x + 4)

\frac{1}{2} y - \frac{1}{3} y - \frac{3}{11} y = \frac{1}{2}

∣ 6 - x ∣ = 10

\frac{6 + 7 i}{6 - 7 i}

3 (p - 3) - 5 p > - 3 p - 6

1 \leq 2 x - 1 \leq 5