What is the answer to 5+bi=(a+bi^2) ?

The answer to 5+bi=(a+bi^2) is a=5,b=0

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5+bi=(a+bi^2)

5 + bi = (a + b i^{2})

a = 5, b = 0

Solution steps

5 + bi = (a + b i^{2})

Simplify

a + b i^{2} : a - b

5 + bi = a - b

Rewrite

a - b

in standard complex form:

(a - b) + 0 i

5 + bi = (a - b) + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[5 = a - b b = 0]

[5 = a - b b = 0] : a = 5, b = 0

a = 5, b = 0

z, (2 - i) z + 8 z^{2} = 0

(4 + i) x + (9 - 2 i) y = - 57 + 24 i

x 2 x - 4 y i = 10 - 5 i

z, w = \frac{1}{z + i}

∣ z + 1 + i ∣ = 2