What is the answer to 2x-y+(2x-3y-i)i=0 ?

The answer to 2x-y+(2x-3y-i)i=0 is x=-3/4 ,y=-1/2

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2x-y+(2x-3y-i)i=0

2 x - y + (2 x - 3 y - i) i = 0

x = - \frac{3}{4}, y = - \frac{1}{2}

Solution steps

2 x - y + (2 x - 3 y - i) i = 0

Expand

2 x - y + (2 x - 3 y - i) i : (2 x - y + 1) + i (2 x - 3 y)

(2 x - y + 1) + i (2 x - 3 y) = 0

Rewrite

0

in standard complex form:

0 + 0 i

(2 x - y + 1) + i (2 x - 3 y) = 0 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 x - y + 1 = 0 2 x - 3 y = 0]

[2 x - y + 1 = 0 2 x - 3 y = 0] : x = - \frac{3}{4}, y = - \frac{1}{2}

x = - \frac{3}{4}, y = - \frac{1}{2}

(a + bi)^{2} + 4 (a + bi) = - 4 - 2 i

z^{2} - (2 + 3 i) z - 5 + i = 0

\frac{( 41 + 3 i )}{65} = \frac{1}{x}

i x^{2} - 2 (i + 1) x + 10 = 0

s i y = 33 y + 1

What is the answer to 2x-y+(2x-3y-i)i=0 ?
The answer to 2x-y+(2x-3y-i)i=0 is x=-3/4 ,y=-1/2