What is the answer to (1+4i)/(3-6i)=a+bi ?

The answer to (1+4i)/(3-6i)=a+bi is a=-7/15 ,b= 2/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1+4i)/(3-6i)=a+bi

\frac{1 + 4 i}{3 - 6 i} = a + bi

a = - \frac{7}{15}, b = \frac{2}{5}

Solution steps

\frac{1 + 4 i}{3 - 6 i} = a + bi

Expand

\frac{1 + 4 i}{3 - 6 i} : - \frac{7}{15} + \frac{2 i}{5}

- \frac{7}{15} + \frac{2 i}{5} = a + bi

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- \frac{7}{15} = a \frac{2}{5} = b]

[- \frac{7}{15} = a \frac{2}{5} = b] : a = - \frac{7}{15}, b = \frac{2}{5}

a = - \frac{7}{15}, b = \frac{2}{5}

z^{2} + (1 - 2 i) z + 1 + 5 i = 0

a^{2} + 2 abi - b^{2} = 2 i

a + (b + 1) \cdot i = 4

0.52 + 0.32 bi = (a + b) - 3 i

A i = A - P

What is the answer to (1+4i)/(3-6i)=a+bi ?
The answer to (1+4i)/(3-6i)=a+bi is a=-7/15 ,b= 2/5