What is the answer to (x+y)-16i=12+(x-y)i ?

The answer to (x+y)-16i=12+(x-y)i is x=-2,y=14

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(x+y)-16i=12+(x-y)i

(x + y) - 16 i = 12 + (x - y) i

x = - 2, y = 14

Solution steps

(x + y) - 16 i = 12 + (x - y) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + y = 12 - 16 = x - y]

[x + y = 12 - 16 = x - y] : x = - 2, y = 14

x = - 2, y = 14

z = \frac{2 + ai}{1 - i}

x + y i = 3 i - 4 + 2 - 6 i + \frac{1}{2} i

x (2 - 4 i) - 5 = x - (7 + y i)

l, y = \frac{x}{l in x}

(1 - 2 + 7 i) (x) - 2 y = 0

What is the answer to (x+y)-16i=12+(x-y)i ?
The answer to (x+y)-16i=12+(x-y)i is x=-2,y=14