What is the answer to m^2+n+4i=-3-m^2ni ?

The answer to m^2+n+4i=-3-m^2ni is

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m^2+n+4i=-3-m^2ni

m^{2} + n + 4 i = - 3 - m^{2} ni

(m = 1, m = - 1, n = - 4 n = - 4)

Solution steps

m^{2} + n + 4 i = - 3 - m^{2} ni

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[m^{2} + n = - 3 4 = - m^{2} n]

[m^{2} + n = - 3 4 = - m^{2} n] : (m = 1, m = - 1, n = - 4 n = - 4)

(m = 1, m = - 1, n = - 4 n = - 4)

\frac{a + 2 i}{b - 3 i} = 1 + i

(a + bi)^{2} = - 3 - 4 i

z^{2} - z = 5 - 5 i

(1 + 3 i) z^{2} + (5 + 6 i) z + 7 - 6 i = 0

(x + i y)^{2} + i (x - i y) = 2 i^{2}