What is the answer to i(x+iy)=x+i+i2y ?

The answer to i(x+iy)=x+i+i2y is x= 1/3 ,y=-1/3

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i(x+iy)=x+i+i2y

i (x + i y) = x + i + i 2 y

x = \frac{1}{3}, y = - \frac{1}{3}

Solution steps

i (x + i y) = x + i + i 2 y

Simplify

- y + i x = x + i (1 + 2 y)

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- y = x x = 1 + 2 y]

[- y = x x = 1 + 2 y] : x = \frac{1}{3}, y = - \frac{1}{3}

x = \frac{1}{3}, y = - \frac{1}{3}

4 - i x = y - 3 i

a^{2} i - b^{2} i = - a^{2} + b^{2} i l

4 = \frac{x}{2} + \frac{x - y}{8 + 6 i}

(a + i) (2 + bi) = - 6 + 22 i

- \frac{1}{z - i} - z = 0

What is the answer to i(x+iy)=x+i+i2y ?
The answer to i(x+iy)=x+i+i2y is x= 1/3 ,y=-1/3