What is the answer to (x+yi)-(-6+14i)=18+2i ?

The answer to (x+yi)-(-6+14i)=18+2i is x=12,y=16

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(x+yi)-(-6+14i)=18+2i

(x + y i) - (- 6 + 14 i) = 18 + 2 i

x = 12, y = 16

Solution steps

(x + y i) - (- 6 + 14 i) = 18 + 2 i

Rewrite

(x + y i) - (- 6 + 14 i)

in standard complex form:

(x + 6) + (y - 14) i

(x + 6) + (y - 14) i = 18 + 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 6 = 18 y - 14 = 2]

[x + 6 = 18 y - 14 = 2] : x = 12, y = 16

x = 12, y = 16

(6 i)^{2} + x^{2} = 100

y^{2} + y^{2} i + 6 + i = 2 x + i x

z^{2} - 5 + 12 i = 0

x, y sin (y) - 2 - 5 x^{2} = 0

z^{2} + (3 - i) z + (2 + i) = 0

What is the answer to (x+yi)-(-6+14i)=18+2i ?
The answer to (x+yi)-(-6+14i)=18+2i is x=12,y=16