What is the answer to (-2-6i)-p(4-2i)=qi ?

The answer to (-2-6i)-p(4-2i)=qi is p=-1/2 ,q=-7

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(-2-6i)-p(4-2i)=qi

(- 2 - 6 i) - p (4 - 2 i) = q i

p = - \frac{1}{2}, q = - 7

Solution steps

(- 2 - 6 i) - p (4 - 2 i) = q i

Rewrite

(- 2 - 6 i) - p (4 - 2 i)

in standard complex form:

(- 2 - 4 p) + (- 6 + 2 p) i

(- 2 - 4 p) + (- 6 + 2 p) i = q i

Rewrite

q i

in standard complex form:

0 + q i

(- 2 - 4 p) + (- 6 + 2 p) i = 0 + q i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- 2 - 4 p = 0 - 6 + 2 p = q]

[- 2 - 4 p = 0 - 6 + 2 p = q] : p = - \frac{1}{2}, q = - 7

p = - \frac{1}{2}, q = - 7

(x - y i) + (y + x i) = (5 + i)

x, g (3 - i) = x^{2} - 6 x

(x + 4) i - (y - 3) j = 2 y (i + j)

x^{2} + 2 y i + 2 x y i + 2 x - y^{2} + 1 + i = 0

2 i x^{2} + 2 x + 9 i = 0

What is the answer to (-2-6i)-p(4-2i)=qi ?
The answer to (-2-6i)-p(4-2i)=qi is p=-1/2 ,q=-7