What are the solutions to the equation (x-2)(x+3)=0 ?

The solutions to the equation (x-2)(x+3)=0 are x=2,x=-3

Find the zeros of (x-2)(x+3)=0

The zeros of (x-2)(x+3)=0 are x=2,x=-3

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(x - 2) (x + 3) = 0

x = 2, x = - 3

Solution steps

(x - 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

\frac{3 x}{2} + 3 x + 90 = 180

2^{4}

x = \frac{450 ( 2000 )}{( \frac{π 3 8 ^{2}}{4} ) 120}

12 x^{- 6} y^{10} \cdot 3 x^{7} y

\frac{3 n ^{- 5}}{- 2 ( n ^{4} ) ^{3}}

What are the solutions to the equation (x-2)(x+3)=0 ?
The solutions to the equation (x-2)(x+3)=0 are x=2,x=-3
Find the zeros of (x-2)(x+3)=0
The zeros of (x-2)(x+3)=0 are x=2,x=-3