What is the answer to (x+3)+4i=2+(y-2)i ?

The answer to (x+3)+4i=2+(y-2)i is x=-1,y=6

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(x+3)+4i=2+(y-2)i

(x + 3) + 4 i = 2 + (y - 2) i

x = - 1, y = 6

Solution steps

(x + 3) + 4 i = 2 + (y - 2) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + 3 = 2 4 = y - 2]

[x + 3 = 2 4 = y - 2] : x = - 1, y = 6

x = - 1, y = 6

2 z^{2} - 7 z + 4 = i (2 z + 1)

x + 2 + 7 i = y i - 2

i (x) = - x^{2} + 80 x + 650

(1 + i) (x + 2 y) + (3 - 2 i) (x - y) = 8 + 3 i 3 i

3 x + (y - x) i = 6

What is the answer to (x+3)+4i=2+(y-2)i ?
The answer to (x+3)+4i=2+(y-2)i is x=-1,y=6