What is the answer to 3ai-b-3i=a-5+bi ?

The answer to 3ai-b-3i=a-5+bi is a=2,b=3

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3ai-b-3i=a-5+bi

3 ai - b - 3 i = a - 5 + bi

a = 2, b = 3

Solution steps

3 ai - b - 3 i = a - 5 + bi

Rewrite

3 ai - b - 3 i

in standard complex form:

- b + (3 a - 3) i

- b + (3 a - 3) i = a - 5 + bi

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[- b = a - 5 3 a - 3 = b]

[- b = a - 5 3 a - 3 = b] : a = 2, b = 3

a = 2, b = 3

∣ z - 1 + 3 i ∣ = 2

∣ x + bi + 1 + i ∣ = 1

(z^{2} + i) = 0

4 - x i = y - 3 i

i (t) = t^{2} - 2 t + 1

What is the answer to 3ai-b-3i=a-5+bi ?
The answer to 3ai-b-3i=a-5+bi is a=2,b=3