What is the answer to x+2yi=(1+3i)(1+i) ?

The answer to x+2yi=(1+3i)(1+i) is x=-2,y=2

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x+2yi=(1+3i)(1+i)

x + 2 y i = (1 + 3 i) (1 + i)

x = - 2, y = 2

Solution steps

x + 2 y i = (1 + 3 i) (1 + i)

Simplify

(1 + 3 i) (1 + i) : - 2 + 4 i

x + 2 y i = - 2 + 4 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x = - 2 2 y = 4]

[x = - 2 2 y = 4] : x = - 2, y = 2

x = - 2, y = 2

\frac{( 4 + x i )}{2 + i} = y + 2 i

2 x + 7 + (3 - y) i = - 4 + 6 i

a + bi = (a - bi)^{2}

z^{2} - (2 + 2 i) z + (1 + 2 i) = 0

(x + y \cdot i)^{2} = i

What is the answer to x+2yi=(1+3i)(1+i) ?
The answer to x+2yi=(1+3i)(1+i) is x=-2,y=2