What is the answer to (2+i)x+7y=1+2i,(1-i)x-iy=4-i ?

The answer to (2+i)x+7y=1+2i,(1-i)x-iy=4-i is x=2,y=-3/7

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(2+i)x+7y=1+2i,(1-i)x-iy=4-i

(2 + i) x + 7 y = 1 + 2 i, (1 - i) x - i y = 4 - i

x = 2, y = - \frac{3}{7}

Solution steps

(2 + i) x + 7 y = 1 + 2 i

Rewrite

(2 + i) x + 7 y

in standard complex form:

(2 x + 7 y) + x i

(2 x + 7 y) + x i = 1 + 2 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[2 x + 7 y = 1 x = 2]

[2 x + 7 y = 1 x = 2] : x = 2, y = - \frac{3}{7}

x = 2, y = - \frac{3}{7}

x + y i + (x - y i)^{2} = 4

i (x) = \frac{x - 1}{x + 3}

3 a^{2} - 3 b^{2} - i 6 ab = g (a + bi)

a - bi = ai + b i^{2}

i^{2} + x^{2} = 1

What is the answer to (2+i)x+7y=1+2i,(1-i)x-iy=4-i ?
The answer to (2+i)x+7y=1+2i,(1-i)x-iy=4-i is x=2,y=-3/7