What is the answer to y-8=3(x+1)in ?

The answer to y-8=3(x+1)in is x=-1,y=8,\quad n\ne 0

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y-8=3(x+1)in

y - 8 = 3 (x + 1) in

x = - 1, y = 8, n \neq = 0

Solution steps

y - 8 = 3 (x + 1) in

Rewrite

y - 8

in standard complex form:

(y - 8) + 0 i

(y - 8) + 0 i = 3 (x + 1) in

Rewrite

3 (x + 1) in

in standard complex form:

0 + (3 n x + 3 n) i

(y - 8) + 0 i = 0 + (3 n x + 3 n) i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[y - 8 = 0 0 = 3 n x + 3 n]

[y - 8 = 0 0 = 3 n x + 3 n] : x = - 1, y = 8, n \neq = 0

x = - 1, y = 8, n \neq = 0

x, R s i R (x) = 8 - 2 x + x^{2}

3 x - 200 s i \cdot = - 10

i (x) = - x^{2} + 60 x

m, (m - n)^{2} = - 2 i

z^{2} + (i - z) z + (3 - i) = 0

What is the answer to y-8=3(x+1)in ?
The answer to y-8=3(x+1)in is x=-1,y=8,\quad n\ne 0