What is the answer to solvefor c,i= d/((1-c)) ?

The answer to solvefor c,i= d/((1-c)) is c=1+di

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solvefor c,i= d/((1-c))

solve for

c, i = \frac{d}{( 1 - c )}

c = 1 + d i

Solution steps

i = \frac{d}{( 1 - c )}

Substitute

c = x + y i

i = \frac{d}{1 - ( x + y i )}

Multiply both sides by

1 - x - i y

i (1 - x - i y) = \frac{d}{1 - ( x + y i )} (1 - x - i y)

Expand

y + i (1 - x) = d

Rewrite

d

in standard complex form:

d + 0 i

y + i (1 - x) = d + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[y = d 1 - x = 0]

[y = d 1 - x = 0] : x = 1, y = d

Substitute back

c = x + y i

c = 1 + d i

(a + i)^{2} = 8 + bi

\frac{3 + ai}{5 + bi} = 3 + 5 i

z^{2} + (- 3 + 2 i) z + (5 - i) = 0

x, (x + y)^{2} = 3 - 4 i

z^{2} = 3 + 3 i

What is the answer to solvefor c,i= d/((1-c)) ?
The answer to solvefor c,i= d/((1-c)) is c=1+di