What is the answer to x(1+i)+y(1-i)=0 ?

The answer to x(1+i)+y(1-i)=0 is x=0,y=0

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x(1+i)+y(1-i)=0

x (1 + i) + y (1 - i) = 0

x = 0, y = 0

Solution steps

x (1 + i) + y (1 - i) = 0

Rewrite

x (1 + i) + y (1 - i)

in standard complex form:

(x + y) + (x - y) i

(x + y) + (x - y) i = 0

Rewrite

0

in standard complex form:

0 + 0 i

(x + y) + (x - y) i = 0 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[x + y = 0 x - y = 0]

[x + y = 0 x - y = 0] : x = 0, y = 0

x = 0, y = 0

7 i - 3 j = a (i - j) + b (i + j)

x^{2} + 6 x i - 9 = (5 + 12 i) y

3 x + 8 i = 12 - 12

x i + y^{2} (1 + i) = 3 - 2 i

(x + i y)^{2} + 2 (x - i y) = 2 (x + i y)

What is the answer to x(1+i)+y(1-i)=0 ?
The answer to x(1+i)+y(1-i)=0 is x=0,y=0