What is the answer to 4x+i(3x-y)=3-i^6 ?

The answer to 4x+i(3x-y)=3-i^6 is x=1,y=3

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4x+i(3x-y)=3-i^6

4 x + i (3 x - y) = 3 - i^{6}

x = 1, y = 3

Solution steps

4 x + i (3 x - y) = 3 - i^{6}

Simplify

3 - i^{6} : 4

4 x + i (3 x - y) = 4

Rewrite

4

in standard complex form:

4 + 0 i

4 x + i (3 x - y) = 4 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[4 x = 4 3 x - y = 0]

[4 x = 4 3 x - y = 0] : x = 1, y = 3

x = 1, y = 3

- x^{2} + 6 i x + 8 = 0

2 x + 3 y i = 10 + 18 i

(x + y i)^{2} = 3 + 4 i

3 x + 5 y - 7 = - 2 i y + i x + 5 i

r = 6 e^{\frac{π}{3} i}

What is the answer to 4x+i(3x-y)=3-i^6 ?
The answer to 4x+i(3x-y)=3-i^6 is x=1,y=3