What is the answer to 2x+3ix-3iy+4iy+x-y=-400 ?

The answer to 2x+3ix-3iy+4iy+x-y=-400 is x=-200/3 ,y=200

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2x+3ix-3iy+4iy+x-y=-400

2 x + 3 i x - 3 i y + 4 i y + x - y = - 400

x = - \frac{200}{3}, y = 200

Solution steps

2 x + 3 i x - 3 i y + 4 i y + x - y = - 400

Rewrite

2 x + 3 i x - 3 i y + 4 i y + x - y

in standard complex form:

(3 x - y) + (3 x + y) i

(3 x - y) + (3 x + y) i = - 400

Rewrite

- 400

in standard complex form:

- 400 + 0 i

(3 x - y) + (3 x + y) i = - 400 + 0 i

Complex numbers can be equal only if their real and imaginary parts are equalRewrite as system of equations:

[3 x - y = - 400 3 x + y = 0]

[3 x - y = - 400 3 x + y = 0] : x = - \frac{200}{3}, y = 200

x = - \frac{200}{3}, y = 200

10 + 6 Yi = 5 X + 24 i

z^{2} + 3 + i = 0

a b^{2} \cdot 0 = 0

y e^{x} = 0

ab = 0

What is the answer to 2x+3ix-3iy+4iy+x-y=-400 ?
The answer to 2x+3ix-3iy+4iy+x-y=-400 is x=-200/3 ,y=200