What is |3x^2+2|<4x^2 ?

The solution to |3x^2+2| sqrt(2)

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|3x^2+2|<4x^2

3 x^{2} + 2 < 4 x^{2}

x < - 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (2, \infty)

Decimal Notation

x < - 1.41421 \dots or x > 1.41421 \dots

Solution steps

3 x^{2} + 2 < 4 x^{2}

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

(x < - 2 or x > 2)

Merge Overlapping Intervals

x < - 2 or x > 2

3 (\frac{3}{4})

- \frac{1}{2} x^{- 2} y^{- 4}

2 x^{2} + 19 x + 24

\frac{1. 9 ^{2} - 4}{1.9 - 2}

z^{9} - 3 z^{3} + 2 z^{2}

What is |3x^2+2|<4x^2 ?
The solution to |3x^2+2|<4x^2 is x<-sqrt(2)\lor x>sqrt(2)