What are the solutions to the equation (x-4)^2-31=30 ?

The solutions to the equation (x-4)^2-31=30 are x=sqrt(61)+4,x=-sqrt(61)+4

Find the zeros of (x-4)^2-31=30

The zeros of (x-4)^2-31=30 are x=sqrt(61)+4,x=-sqrt(61)+4

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(x - 4)^{2} - 31 = 30

x = 61 + 4, x = - 61 + 4

Decimal Notation

x = 11.81024 \dots, x = - 3.81024 \dots

Solution steps

(x - 4)^{2} - 31 = 30

Move

31

to the right side

(x - 4)^{2} = 61

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 61 : x = 61 + 4

Solve

x - 4 = - 61 : x = - 61 + 4

The solutions to the quadratic equation are:

x = 61 + 4, x = - 61 + 4

3 (2 v + 8) = 60

\frac{( - 2 m ^{4} ) ^{2}}{8 m ^{2}}

\frac{5 b ^{- 2}}{b ^{- 3}}

∣ 2 x + 3 ∣ + 5 < 4

(x - 5)^{2} = 25

What are the solutions to the equation (x-4)^2-31=30 ?
The solutions to the equation (x-4)^2-31=30 are x=sqrt(61)+4,x=-sqrt(61)+4
Find the zeros of (x-4)^2-31=30
The zeros of (x-4)^2-31=30 are x=sqrt(61)+4,x=-sqrt(61)+4