What is the answer to (x+2)(y-1)^3(2x-1)=0 ?

The answer to (x+2)(y-1)^3(2x-1)=0 is x=-2,y=1,x= 1/2

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(x+2)(y-1)^3(2x-1)=0

(x + 2) (y - 1)^{3} (2 x - 1) = 0

x = - 2, y = 1, x = \frac{1}{2}

Decimal Notation

x = - 2, y = 1, x = 0.5

Solution steps

(x + 2) (y - 1)^{3} (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or y - 1 = 0 or 2 x - 1 = 0

Solve

x + 2 = 0 : x = - 2

Solve

y - 1 = 0 : y = 1

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = - 2, y = 1, x = \frac{1}{2}

a ((1) e^{- 6 t} - (t) 6 e^{- 6 t}) = 0

x^{2} y + x y - k^{2} y = 0

t e^{t} (c - 2 x) = 0

∣ a ∣ b = 0

- 2 x e^{y} = 0

What is the answer to (x+2)(y-1)^3(2x-1)=0 ?
The answer to (x+2)(y-1)^3(2x-1)=0 is x=-2,y=1,x= 1/2