What are the solutions to the equation 4x^2+5x-5=0 ?

The solutions to the equation 4x^2+5x-5=0 are x=(-5+sqrt(105))/8 ,x=(-5-sqrt(105))/8

Find the zeros of 4x^2+5x-5=0

The zeros of 4x^2+5x-5=0 are x=(-5+sqrt(105))/8 ,x=(-5-sqrt(105))/8

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4 x^{2} + 5 x - 5 = 0

x = \frac{- 5 + 105}{8}, x = \frac{- 5 - 105}{8}

Decimal Notation

x = 0.65586 \dots, x = - 1.90586 \dots

Solution steps

4 x^{2} + 5 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 5) = 105

x_{1, 2} = \frac{- 5 \pm 105}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 105}{2 \cdot 4}, x_{2} = \frac{- 5 - 105}{2 \cdot 4}

x = \frac{- 5 + 105}{2 \cdot 4} : \frac{- 5 + 105}{8}

x = \frac{- 5 - 105}{2 \cdot 4} : \frac{- 5 - 105}{8}

The solutions to the quadratic equation are:

x = \frac{- 5 + 105}{8}, x = \frac{- 5 - 105}{8}

k - 33 \geq 0

\frac{1}{6} - \frac{1}{4} + \frac{1}{10}

6 y^{2} + 17 y + 7

x^{4} - 2 x^{3} + 8 x - 16

3.8 x = 2.736

What are the solutions to the equation 4x^2+5x-5=0 ?
The solutions to the equation 4x^2+5x-5=0 are x=(-5+sqrt(105))/8 ,x=(-5-sqrt(105))/8
Find the zeros of 4x^2+5x-5=0
The zeros of 4x^2+5x-5=0 are x=(-5+sqrt(105))/8 ,x=(-5-sqrt(105))/8