Solution
simplify
Solution
Solution steps
Apply exponent rule:
Apply exponent rule: assuming
Apply rule:
Popular Examples
(1/3)^3= 1/27simplify \sqrt[3]{35}simplify simplify ln(1/(sqrt(e)))simplify | p/(p-96)|=e^{((40ln(5/3)))/(40)}4x-5(x^2-1)=x(2-x)+5
Frequently Asked Questions (FAQ)
What is k^{-4}j^0 ?
The solution to k^{-4}j^0 is 1/(k^4)