What is the answer to M(2x^2+128x-4096)=0 ?

The answer to M(2x^2+128x-4096)=0 is M=0,x=32(sqrt(3)-1),x=-32(1+sqrt(3))

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M(2x^2+128x-4096)=0

M (2 x^{2} + 128 x - 4096) = 0

M = 0, x = 32 (3 - 1), x = - 32 (1 + 3)

Decimal Notation

M = 0, x = 23.42562 \dots, x = - 87.42562 \dots

Solution steps

M (2 x^{2} + 128 x - 4096) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

M = 0 or 2 x^{2} + 128 x - 4096 = 0

M = 0

Solve

2 x^{2} + 128 x - 4096 = 0 : x = 32 (3 - 1), x = - 32 (1 + 3)

The solutions are

M = 0, x = 32 (3 - 1), x = - 32 (1 + 3)

I n (x) = 0

0 = (1 - v^{2}) t

(x - 1) (y - 1) = 0

y, y 4 x - y = 0

x + 2 e^{- 4 t} x = 0

What is the answer to M(2x^2+128x-4096)=0 ?
The answer to M(2x^2+128x-4096)=0 is M=0,x=32(sqrt(3)-1),x=-32(1+sqrt(3))