What is the answer to x(x-1)(x-2)y+4x(x-1)y+xy-y=0 ?

The answer to x(x-1)(x-2)y+4x(x-1)y+xy-y=0 is y=0,x=-1,x=1

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x(x-1)(x-2)y+4x(x-1)y+xy-y=0

x (x - 1) (x - 2) y + 4 x (x - 1) y + x y - y = 0

y = 0, x = - 1, x = 1

Solution steps

x (x - 1) (x - 2) y + 4 x (x - 1) y + x y - y = 0

Factor

x (x - 1) (x - 2) y + 4 x (x - 1) y + x y - y : y (x + 1)^{2} (x - 1)

y (x + 1)^{2} (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or x + 1 = 0 or x - 1 = 0

y = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

y = 0, x = - 1, x = 1

(x + 5) (y - 1) = 0

q^{2} ∣ q ∣ = 0

I n x + I n (x - 2) = 0

xv = 0

0 = x ∣ x ∣

What is the answer to x(x-1)(x-2)y+4x(x-1)y+xy-y=0 ?
The answer to x(x-1)(x-2)y+4x(x-1)y+xy-y=0 is y=0,x=-1,x=1