What are the solutions to the equation (5x-2)^2-7=0 ?

The solutions to the equation (5x-2)^2-7=0 are x=(sqrt(7)+2)/5 ,x=(-sqrt(7)+2)/5

Find the zeros of (5x-2)^2-7=0

The zeros of (5x-2)^2-7=0 are x=(sqrt(7)+2)/5 ,x=(-sqrt(7)+2)/5

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(5 x - 2)^{2} - 7 = 0

x = \frac{7 + 2}{5}, x = \frac{- 7 + 2}{5}

Solution steps

(5 x - 2)^{2} - 7 = 0

Move

7

to the right side

(5 x - 2)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 2 = 7 : x = \frac{7 + 2}{5}

Solve

5 x - 2 = - 7 : x = \frac{- 7 + 2}{5}

The solutions to the quadratic equation are:

x = \frac{7 + 2}{5}, x = \frac{- 7 + 2}{5}

x^{2} + 6 x \leq - 8

- 9 < 2 x - 3 < 5

- 2 \cdot 5

\frac{25}{169}

x + 50 = 5

What are the solutions to the equation (5x-2)^2-7=0 ?
The solutions to the equation (5x-2)^2-7=0 are x=(sqrt(7)+2)/5 ,x=(-sqrt(7)+2)/5
Find the zeros of (5x-2)^2-7=0
The zeros of (5x-2)^2-7=0 are x=(sqrt(7)+2)/5 ,x=(-sqrt(7)+2)/5