What is the answer to x^2+2xyparax=0 ?

The answer to x^2+2xyparax=0 is x=0,y=-1/(2pa^2r);\quad p\ne 0

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x^2+2xyparax=0

x^{2} + 2 x y p a r a x = 0

x = 0, y = - \frac{1}{2 p a ^{2} r}; p \neq = 0

Solution steps

x^{2} + 2 x y p a r a x = 0

Factor out common term

x^{2}

x^{2} (1 + 2 y p a^{2} r) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 1 + 2 p a^{2} ry = 0

x = 0

Solve

1 + 2 p a^{2} ry = 0 : y = - \frac{1}{2 p a ^{2} r}; p \neq = 0

The solutions are

x = 0, y = - \frac{1}{2 p a ^{2} r}; p \neq = 0

3 x^{2} y^{4} = 0, 4 x^{3} y^{3} = 0

2 ab = 0

- 2 ∣ x + 5 ∣ (x + 3.1) = 0

ln (3 - x) a t x = 0

se x = 0

What is the answer to x^2+2xyparax=0 ?
The answer to x^2+2xyparax=0 is x=0,y=-1/(2pa^2r);\quad p\ne 0